Skip to main content

codeforces-even odds 

#include<iostream>
using namespace std;
int main()
{
 long long n,k;
 cin>>n>>k;
 long long t=(n+1)/2;
 if(k<=t)
  cout<<2*k-1;
 else
  cout<<(k-t)*2;
 return 0;
}

Comments

Post a Comment

Popular posts from this blog

Finding permutations of a string using recursion

#include<bits/stdc++.h> using namespace std; void print_perm(char str[],int k,int n) {     if(k==n)         cout<<str<<endl;     else     {         for(int i=k;i<n;i++)         {             swap(str[k],str[i]);             print_perm(str,k+1,n);             swap(str[k],str[i]);         }     } } int main() {     char str[20];     cout<<"Enter a string"<<endl;     cin>>str;     print_perm(str,0,strlen(str));     return 0; }
Post a Comment
Read more

Reversing a stack using recursion

#include<bits/stdc++.h> using namespace std; stack<int> s2; void rev(stack<int> s) {     if(!s.empty())     {         int temp=s.top();         s.pop();         s2.push(temp);         rev(s);     } } void display(stack<int> s) {     while(!s.empty())     {         cout<<s.top()<<" ";         s.pop();     }     cout<<endl; } int main() {      stack<int> s;      int n;      cout<<"Enter the number of elements to push onto stack"<<endl;      cin>>n;      for (int i = 0; i < n; ++i)      {       ...
Post a Comment
Read more

BFS of a graph

#include<bits/stdc++.h> using namespace std; class graph {     int v;     list<int> *adj; public:     graph(int v)     {         this->v=v;         adj=new list<int>[v];     }     void add_edge(int v,int w)     {         adj[v].push_back(w);     }     void bfs(int start); }; void graph:: bfs(int start) {     bool *visited=new bool[v];     for(int i=0;i<v;i++)         visited[i]=false;     visited[start]=true;     list<int> queue;     queue.push_back(start);     while(!queue.empty())     {         int s=queue.front();         cout<<s<...
Post a Comment
Read more